Question

Log2 1 is defined
True
False

Answer 1

Answer: True

Through the change of base formula, we can say,

`\log_(2)(1) = (\log(1))/(\log(2)) = (0)/(\log(2)) = 0`

So in short,

`\log_(2)(1)=0`

It turns out that

`\log_(b)(1) = 0`

for real numbers b such that b > 0 and
`b \\e 1`