Final answer:
To calculate the electric flux through each face of a cube with a charge q = 6.10-6 C at its center, we need to use Gauss's law. The electric flux through each face is equal to the electric field strength multiplied by the surface area of the face. In this case, since the cube is symmetrical, the electric flux through each face will be the same.
Step-by-step explanation:
To calculate the electric flux through each face of a cube with a charge q = 6.10-6 C at its center, we need to use Gauss's law. The electric flux through each face is equal to the electric field strength multiplied by the surface area of the face. In this case, since the cube is symmetrical, the electric flux through each face will be the same.
Given:
- Charge, q = 6.10-6 C
- Edge length of the cube, a
To find the electric flux, we need to calculate the electric field strength (E). The electric field strength at a point due to a point charge is given by the equation:
E = k * q / r^2
Where:
- k = Coulomb's constant = 8.99 * 10^9 N*m^2/C^2
- q = Charge
- r = Distance from the charge
Using this equation, we can find the electric flux through each face of the cube by calculating the electric field strength at each face and multiplying it by the surface area of the face.