Answer:
We reject H₀, we have enough argument to explain that the production line is out of control. Is producing sprinkler out of specification
Explanation:
Data information:
27 41 22 27 23 35 30 33 24 27 28 22 24
sample size n = 13
sample mean x = 27.92
sample standard deviation s = 5.39
The manufacturing process under control will always produce an output with normal distribution, in this case as n < 30 we will use t-student distribution in our test.
Hypothesis Test:
Null Hypothesis H₀ x = 25
Alternative Hypothesis Hₐ x > 25
The Alternative hypothesis indicates that the test is a one-tail test.
Significance level is α = 0.05
From z-table and for α = 0.05 and df = n - 1 df = 13 - 1 df = 12
p-value = 1.782
t(s) = ( x - 25 ) / s/√n
t(s) = ( 27.92 - 25 )/ 5.39/√13
t(s) = 2.92*3.605/ 5.39
t(s) = 1.95
From t-table df = 12 we find that 1.95 corresponds to a p-value < 0.05
then as p-value < 0.05 we are in the rejection region for H₀ then we reject H₀. We can deduce that the production line for sprinkler is given products out of specification