Question

How to factor z²-4z+4

Answer 1

`\implies {\blue {\boxed {\boxed {\purple {\sf { \: ({ \: z - 2 \: })^(2) \: }}}}}}`

`\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}`

`{z}^(2) - 4z + 4`

`= {z}^(2) - 2z - 2z + 4`

Taking "
`z`" as common from first two terms and "
`2`" from last two terms, we have

`= z \: ( \: z - 2 \: ) - 2 \: ( \: z - 2 \: )`

Taking the factor
`(z-2)` as common,

`= ( \: z - 2 \: )( \: z - 2 \: )`

`= {( \: z - 2 \: )}^(1 + 1)`

`= ({ \: z - 2 \: })^(2)`

`\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35❦}}}}}`