Question

A cylindrical space capsule lands in the ocean. This capsule is 2.44 m long, 1.10 m in diameter, and weighted at one end so that it floats with its long central axis vertical and 0.820 m of its length above the water surface. The mass density of sea water is 1025 kg/m3.What is the magnitude of the buoyant force exerted on the capsule?

Answer 1

The correct answer is "15456.8 N".

Step-by-step explanation:

According to the question,

The inside volume will be:

=
`3.14* ((1.1)/(2) )^2* (2.44-0.82)`

=
`3.14* (1.21)/(4)* 1.62`

=
`3.14* 03025* 1.62`

=
`1.538757 \ m^3`

hence,

The buoyant force will be:

=
`V* Pw* g`

=
`1.538757* 1025* 9.8`

=
`15456.8 \ N`