Question

find the equation of a line that passes through (3 1) and ia parallel to y=1-2x leave your answer in the form of y=mx+c

Answer 1

y = -2x+7

Explanation:

Parallel lines have the same slope

y = 1-2x has a slope of -2

So the new line has a slope of -2

We have a slope of -2 and a point of (3,1)

y = mx+c

1 = -2(3)+c

1 = -6+c

Add 6 to each side

1+6 =c

7 =c

y = -2x+7