Question

Can someone do this fast ? I need it for tomorrow

Answer 1

Explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to
`3x^2+x-1`.

hg(x) =
`x^2(x+2)` which simplifies to

`x^3+2x^2`. Now set that equal to
`3x^2+x-1`:

`x^3+2x^2=3x^2+x-1` and get everything on the same side and factor:

`x^3-x^2-x+1=0`. Factor by grouping:

`(x^3-x^2)-(x+1)=0` and factor out what's common in each set of ( ):

`x^2(x-1)-1(x-1)=0` which factors out to

`(x^2-1)(x-1)=0`. But
`x^2-1` factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1