Answer:
![n=46.8molLa\\\\m=6.50x10^3gLa](https://img.qammunity.org/2022/formulas/chemistry/college/4ijxb2b4pcc1pjofckd9ro221lisnczcik.png)
Step-by-step explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate both moles and grams of lanthanum by using the Avogadro's number as a relationship of atoms to moles and its atomic mass as a relationship to moles to grams to obtain the following:
![n=2.82x10^(25)atomsLa*(1molLa)/(6.022x10^(23)atomsLa)=46.8molLa\\\\m=46.8molLa*(138.9gLa)/(1molLa) =6.50x10^3gLa](https://img.qammunity.org/2022/formulas/chemistry/college/sw4kko96nbjuj1j3r25qtahood5kzsg4qh.png)
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