Question

To make it more easier for everyone, it's on Khan Academy and this problem is in Algebra 1 to be specific. Solve for x.

3x−8≤23 AND −4x+26≥6
Choose 1 answer:
A: x ≤ 31/3
B: x ≤ 5
C: 5 ≤ x ≤ 31/3
D: There are no solutions
E: All values of x are solutions

Answer 1

B: x≤5

Explanation:

Hi there!

We're given two inequalities; 3x−8≤23 and −4x+26≥6

We need to find the values of x that make BOTH of the inequalities true (which is the intersection of the two inequality graphs)

First, let's solve for x in both of them

taking the first inequality:

3x−8≤23

add 8 to both sides

3x≤31

divide by 3

x≤31/3

now solve for x in −4x+26≥6

subtract 26 from both sides

-4x≥-20

divide both sides by -4 and remember to FLIP the inequality sign since we have a negative number

x≤5

now let's graph these two inequalities to find the intersection, and that is below with the answer

Hope this helps! :)