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Graph (x-4)^2/4 + y^2/9 = 1

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Answer:

see attached

Explanation:

Compare the equation to that of an ellipse with center (h, k) and axes of lengths 2a and 2b.

((x -h)/a)^2 +((y -k)/b)^2 = 1

We see that (h, k) = (4, 0) and a=2, b=3.

This tells us the center of the ellipse is (4, 0), the major axis is parallel to the y-axis, and the minor axis is parallel to the x-axis. The ellipse extends ±2 units from its center in the x-direction and ±3 units from its center in the y-direction.

Graph (x-4)^2/4 + y^2/9 = 1-example-1
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