Answer:
Part A
The volume of the triangular prism is 500 cm³
Part B
The total surface area of the prism is approximately 441.42 cm²
Explanation:
The given details are;
The dimensions of the side length of the cube, s = 10 cm
The shape the cube was cut across to obtain = A prism
Part A
Whereby the prism obtained is a triangular prism, we have;
The cube can be cut in half to form a triangular prism
The volume of each triangular prism obtained = (1/2) × The volume of the cube
∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³
Part B
The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism
The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50
The square cross sectional area, A₂ = 10 × 10 = 100
The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2
The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃
∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42
The total surface area of the prism, A ≈ 441.42 cm²