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For f(x) = 4x+1 and g(x) = x^2 -5, find (fxg)(x)

1 Answer

5 votes

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\huge\underline{\tt{\red{Problem:}}}


\quad\quad\quad\quad\tt{f(x) = 4x + 1} \: and \: g(x) = {x}^(2) - 5


\huge\underline{\tt{\red{Fomula:}}}


\quad\quad\quad\quad\huge\tt{( \: f \: • \: g \: )}


\huge\underline{\tt{\red{Solution:}}}


\quad\quad\quad\quad\tt{(f \:•\: g)(x) = (4x + 1} \: ) ( {x}^(2) - 5)

Step by step first:


\quad\tt{ ⟶ { 4x * {x}^(2) = \boxed{4 {x}^(3)}} }


\quad\tt{ ⟶ { 1 * {x}^(2) = \boxed{{x}^(2)}} }


\quad\tt{ ⟶ { 4x * ( - 5) = \boxed{ - 20x}} }


\quad\tt{ ⟶ { 1 * ( - 5) = \boxed{ - 5}} }

It will look like this:


\quad\quad\quad\quad\tt{(f \:•\: g)(x) = (4 {x}^(3) + {x}^(2) - 20x - 5 )}


\huge\underline{\tt{\red{Answer:}}}


\quad\quad \underline{ \boxed{\tt{ \red{(f \:•\: g)(x) = 4 {x}^(3) + {x}^(2) - 20x - 5 }}}}

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✍︎ C.Rose❀

For f(x) = 4x+1 and g(x) = x^2 -5, find (fxg)(x)-example-1
User Velter
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