Question

The centripetal acceleration of an object moving in a circle of radius 20 cm is 8 m/sec ^2. The possible tangential velocity of the object will be

Answer 1

v = 1.26 m/s

Step-by-step explanation:

Given that,

The radius of the circle, r = 20 cm = 0.2 m

The centripetal acceleration of the object, a = 8 m/s²

We need to find the tangential velocity of the object. We know that the formula for the centripetal acceleration is given by :

`a=(v^2)/(r)\\\\v=√(ar)\\\\v=√(8* 0.2)\\\\v=1.26\ m/s`

So, the tangential velocity of the object will be 1.26 m/s.