Question

PLEASE HELP ME SOLVE THIS.Thank you so much!

Answer 1

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Step-by-step explanation:

The given reaction equation is as follows.

`Cr_(2)O^(2-)_(7) + Cl^(-) \rightarrow Cr^(3+) + Cl_(2)`

Now, the two half-reactions can be written as follows.

Reduction half-reaction:
`Cr_(2)O^(2-)_(7) + 3e^(-) \rightarrow Cr^(3+)`

This will be balanced as follows.

`Cr_(2)O^(2-)_(7) + 14H^(+) + 6e^(-) \rightarrow 2Cr^(3+) + 7H_(2)O` ... (1)

Oxidation half-reaction:
`Cl^(-) \rightarrow Cl_(2) + 1e^(-)`

This will be balanced as follows.

`6Cl^(-) \rightarrow 3Cl_(2) + 6e^(-)` ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

`Cr_(2)O^(2-)_(7) + 14H^(+) + 6Cl^(-) \rightarrow 2Cr^(3+) + 3Cl_(2) + 7H_(2)O`

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.