Answer:
3.416 m/s
Step-by-step explanation:
Given that:
mass of cannonball
= 72.0 kg
mass of performer
= 65.0 kg
The horizontal component of the ball initially
= 6.50 m/s
the final velocity of the combined system v = ????
By applying the linear momentum of conservation:
![m_A \mu_(xA)+m_B \mu_(xB) = (m_A+m_B) v](https://img.qammunity.org/2022/formulas/physics/college/mv86xkkeg23abhmkqon00i0gtgoveo3at4.png)
![72.0 \ kg * 6.50 \ m/s+65.0 \ kg * 0 = (72.0 \ kg+65.0 \ kg) v](https://img.qammunity.org/2022/formulas/physics/college/z5tr8xk2fb4yqcfka29gc5h5f4lnribb1w.png)
![468 kg m/s + 0 = (137 kg)v](https://img.qammunity.org/2022/formulas/physics/college/2ciodjd68omaur6uavdc0sajtu6jfl4zkh.png)
![v = (468\ kg m/s )/(137 \ kg)](https://img.qammunity.org/2022/formulas/physics/college/cm20l4aycaywk4voherc2615bb0ii9rejr.png)
v = 3.416 m/s