Question

A 1.00kg object vibrates at the end of a vertical spring. If the frequency of the vibration is 1.25Hz, what is the spring constant?

Answer 1

61.62 N/m

Step-by-step explanation:

Applying,

1/F = 2π
`√(m/k)`.................. Equation 1

Where F = frequency, m = mass of the spring, k = spring constant, π = pie.

make k the subject of the equation

k = m(2πF)²............... Equation 2

From the question,

Given: m = 1.00 kg, F = 1.25 Hz

Constant: π = 3.14

Substitute these values into equation 2

k = 1(2×3.14×1.25)²

k = 61.62 N/m