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Cos(x+pi/3)-sin2x=0 ahihihihihihiihihihihihih
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Cos(x+pi/3)-sin2x=0 ahihihihihihiihihihihihih

User Bitwise Creative
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1 Answer

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Answer:cos(x+pi/3) - sin2x=0

<=> cos(x+pi/3)=sin2x

<=> cos(x+pi/3)=cos(pi/2-2x)

<=>x+pi/3=pi/2-2x+k2pi

Or x+pi/3=-pi/2 +2x+k2pi

<=>x=pi/18 + k2pi/3

Or x=5pi/6 +k2pi

Explanation:

User Stig Hausberg
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