Question

How many atoms are in 10.1 g Ne

Answer 1

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Tables
• Moles

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 10.1 \ g \ Ne((1 \ mol \ Ne)/(20.18 \ g \ Ne))((6.022 \cdot 10^(23) \ atoms \ Ne)/(1 \ mol \ Ne))`
2. [DA] Divide/Multiply [Cancel out units]:
   `\displaystyle 3.01398 \cdot 10^(23) \ atoms \ Ne`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne