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A stock solution of calcium sulfate, CaSO4 has a concentration of 3.00 M. The volume of this solution is 150 mL. What volume of a 1.25 M solution could be made from the stock solution?

1 Answer

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Answer: The volume of stock solution needed is 62.5 mL

Step-by-step explanation:

A solution consists of solute and solvent. A solute is defined as the component that is present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

To calculate the volume of stock solution needed, the formula used is:


C_1V_1=C_2V_2 ....(1)

where,


C_1\text{ and }V_1 are the concentration and volume of stock solution.


C_2\text{ and }V_2 are the concentration and volume of diluted solution.

We are given:


C_1=3.00M\\V_1=?mL\\C_2=1.25M\\V_2=150mL

Putting values in equation 1, we get:


3.00* V_1=1.25* 150\\\\V_1=(1.25* 150)/(3.00)\\\\V_1=62.5mL

Hence, the volume of stock solution needed is 62.5 mL

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