Question

The number of molecules in 17.9 g of CO is

Answer 1

3.85 × 10²³ molecules CO

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Table
• Compounds
• Moles
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

Identify

[Given] 17.9 g CO

[Solve] molecules CO

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of CO: 12.01 + 16.00 = 28.01 g/mol

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 17.9 \ g \ CO((1 \ mol \ CO)/(28.01 \ g \ CO))((6.022 \cdot 10^(23) \ molecules \ CO)/(1 \ mol \ CO))`
2. [DA] Divide/Multiply [Cancel out units]:
   `\displaystyle 3.8484 \cdot 10^(23) \ molecules \ CO`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.8484 × 10²³ molecules CO ≈ 3.85 × 10²³ molecules CO