Question

An opening volumetric cylinder filled with water at volume 0.003m after period of

time the water in the cylinder is just evaporated what is the work done by this process?​

Answer 1

= - 303.975 Joules

Step-by-step explanation:

Given that:

The volume of the cylinder = 0.003 m^3

Now, to liters:

The volume = 0.003 *1000 L

= 3 L

For an open cylinder, we mean the atmospheric pressure is at standard condition.

Thus, the workdone = -PΔV

= - 1 atm (3 L)

= - 3 L atm

1 L atm to Joules

= 101.325 Joules

Therefore;

=- 3* 101.325 Joules

= - 303.975 Joules