Question

Compound EX4 reacts with Y2 giving two products: EX Y and XY. Calculate the E- X bond enthalpy if the reaction liberates 243.6 kJ/mol and other bond enthalpies are:

Y-Y 109 kJ/mol,
X-Y 123.1 kJ/mol and
E-Y 290 kJ/mol.
a. 547.7 kJ/mol
b. 60.5 kJ/mol
c. 234.7 kJ/mol
d. 20.6 kJ/mol
e. 176.9 kJ/mol

Answer 1

Option B

Step-by-step explanation:

From the question we are told that:

Equation

`EX_4+Y_2->EX_3Y+XY`

Bond enthalpies are:

`Y-Y 109 kJ/mol,`

`X-Y 123.1 kJ/mol`

`E-Y 290 kJ/mol.`

Generally the equation for the energy used to break E-X and Y-Y is mathematically given by

`E_2=109+x`

Therefore

Total Energy Liberated is

`E_T=E_1+E_2`

`E_T=413.1+109+x`

`E_T=304.1-x`

Since

`E_T+E_I`

Therefore

`304.1-x=243.6`

`x=60.5kJ/mol`

Option B