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The drama club is running a lemonade stand to raise money for its new production. A local grocery store donated cans of lemonade and bottles of water. Cans of lemonade sell for $2.50 each and bottles of water sell for $1.25 each. The club needs to raise at least $600 to cover the cost of renting costumes. The students can accept a maximum of 460 cans and bottles.

Write a system of inequalities that can be used to represent this situation.

The club sells 144 cans of lemonade. What is the least number of bottles of water that must be sold to cover the cost of renting costumes? Justify your answer

Answer 1

Part A

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

Part B

192 bottles

Explanation:

The given parameters are;

The selling price of a can of lemonade = $2.50

The selling price for each bottle of water = $1.25

The amount the club needs to raise to cover the cost of renting costumes, A = $600

The maximum acceptable cans and bottles = 460

Part A

Let 'x', represent the number of cans of lemonade accepted by the students, and let 'y' represent the number of bottles of water accepted, we have;

The situation can be represented by the following system of inequalities

x + y ≤ 460

2.5·x + 1.25·y ≥ 600

Part B

The number of cans of lemonade sold, x = 144

Therefore, we have;

2.5 × 144 + 1.25·y ≥ 600

1.25·y ≥ 600 - 2.5 × 144 = 240

1.25·y ≥ 240

y ≥ 240/1.25 = 192

y ≥ 192

The least number of bottles of water that must be sold to cover the cost of renting costumes, y = 192 bottles