Question

m to the power of 5 ×m to the power of 6 × n to the power of 11 over m to the power of 3 × n to the power of 5 × n​

Answer 1

`(m^5 * m^6 * n^(11))/(m^3 * n^5 * n^1)`

Explanation:

m to the power of 5 = m⁵

m to the power of 6 = m ⁶

n to the power of 3 = n³

n to the power of 11 = n¹¹

`m^5 * m^6 * n^(11)` over
`m^3 * n^5 * n^1` =
`(m^5 * m^6 * n^(11))/(m^3 * n^5 * n^1)`

Simplified form:

`m^((5+6-3)) * n^((11 - 5- 1)) = m^8 * n^(6)`

Answer 2

Explanation:

`\frac{( {m}^(5) * {m}^(6) * {n}^(11))}{ {m}^(3) * {n}^(5) * n} \\ = \frac{ {m}^(11) * {n}^(11) }{ {m}^(3) * {n}^(6) } \\ = {m}^(8) * {n}^(5) \\ = {m}^(8) {n}^(5)`