Question

Volume of CO2 at STP of 27.0 g​

Answer 1

The volume of CO₂ at STP is equal to 13.73 L.

Step-by-step explanation:

Given mass, m = 27 g

The molar mass of CO₂ = 44 g/mol

Let n is the number of moles. So,

n = given mass/molar mass

`n=(27)/(44)\\\\n=0.613\ \text{moles}`

Let V is the volume of CO₂. So,

V = n×V'

Where

V' is the molar volume = 22.4 L

So,

V = 0.613 × 22.4

V = 13.73 L

Hence, the volume of CO₂ at STP is equal to 13.73 L.