Given:
Cards labelled 1, 3, 5, 6, 8 and 9.
A card is drawn and not replaced. Then a second card is drawn at random.
To find:
The probability of drawing 2 even numbers.
Solution:
We have,
Even number cards = 6, 8
Odd numbers cards = 1, 3, 5, 9
Total cards = 1, 3, 5, 6, 8 and 9
Number of even cards = 2
Number of total cards = 6
So, the probability of getting an even card in first draw is:
![P_1=\frac{\text{Number of even cards}}{\text{Number of total cards}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/s5euh8wepe4ae0i7irgeejg076me7wkyjs.png)
![P_1=(2)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/gy7byfyhvos0eirfstsi5135c83kwk01o5.png)
![P_1=(1)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/hh8h04g6qk4hyjsnip3t0n36h9xa0nsoo0.png)
Now,
Number of remaining even cards = 1
Number of remaining cards = 5
So, the probability of getting an even card in second draw is:
![P_2=\frac{\text{Number of remaining even cards}}{\text{Number of remaining total cards}}](https://img.qammunity.org/2022/formulas/mathematics/high-school/860re9nkfhmjsqm7gjqvh1qzxh52fabyye.png)
![P_2=(1)/(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/d70ud0dwh545yashwe1wj7vyym5bvoe94b.png)
The probability of drawing 2 even numbers is:
![P=P_1* P_2](https://img.qammunity.org/2022/formulas/mathematics/high-school/we08yjbtiqjaytnnaqo0afq75wjere0l7q.png)
![P=(1)/(3)* (1)/(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v0tit50habvbfnqs2yevgk37awcad5p55k.png)
![P=(1)/(15)](https://img.qammunity.org/2022/formulas/mathematics/high-school/74rqx8tbqi6zsvyf4d4qz9wrkzdi5d4o3r.png)
Therefore, the probability of drawing 2 even numbers is
. Hence, the correct option is (b).