Question

What volume will 106.476 g N, gas at STP occupy?

O 85.1808L
O 170.362L
O 7.60543L
0 3.80271L

Answer 1

170.362 L

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Table
• Moles

Gas Laws

• STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

Identify variables

[Given] 106.476 g N

[Solve] L N

Step 2: Identify Conversions

[STP] 1 mol = 22.4 L

[PT] Molar Mass of N: 14.01 g/mol

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 106.476 \ g \ N((1 \ mol \ N)/(14.01 \ g \ N))((22.4 \ L \ N)/(1 \ mol \ N))`
2. [DA] Divide/Multiply [Cancel out units]:
   `\displaystyle 170.24 \ L \ N`