Question

ou charge a piece of aluminum foil (mass = 4.99 g) by touching it to a charged rod. The charged rod gives the aluminum foil a charge of 13 µC. Your professor brings a charged plate over and tells you to put the aluminum foil on top of the plate. To your surprise the aluminum foil hovers motionless in the air above it! Calculate the value of the electric field from the charged plate (assume it is a uniform field and the aluminum foil is a point charge).

Answer 1

The appropriate answer is "3761.69 N/C".

Step-by-step explanation:

Given that:

Mass,

m = 4.99 g

or,

=
`4.99* 10^(-3) \ kg`

Charge,

q = 13 µC

or,

=
`13* 10^(-6) \ C`

As we know,

⇒
`F=mg=Eq`

then,

⇒
`E=(mg)/(q)`

By putting the values, we get

`=(4.99* 10^(-3)* 9.8)/(13* 10^(-6))`

`=3761.69 \ N/C`