Answer:
a) ball K <K₀, b) the speed of the ball after the collision, c) can K> 0
d) can moves in the same direction as the ball
Step-by-step explanation:
a) the kinetic energy is given by
K = ½ M v²
in this case before the collision the kinetic energy of the ball is
K₀ = ½ M v₀²
After the collision the aluminum can has a certain speed, therefore the kinetic energy of the ball must decrease, the velocity of the ball after the collision is
v <v₀
therefore the kinetic energy is
K = ½ m v²
in consecuense
K <K₀
b) an evidence of this fact is to measure the speed of the ball before the collision and the speed of the ball after the collision,
c) In the case of the aluminum can, the initial kinetic energy is ero, because it is stopped
K₀ = 0
after the collision a part of the cal momentum of the ball is transferred to the can, therefore its velocity is different from zero
K = ½ m v_can²
K> 0
d) the clearest evidence of this fact is that the can moves in the same direction as the ball