Answer:
(viii) 116 ± 2.78 x 14.4√5
Explanation:
The given data is
Sample size =n= 5
Calculated t- value= 2.4837
Mean= 116
Standard deviation= sd= 14.40486
The t - value from table with 4 d.f for ∝/2 is t∝/2 (n-1)= 2.776
The 95% confidence interval is calculated by
d` ± t∝/2 (n-1) *sd/√n
Putting the values
116 ± 2.776* 14.40486/√5
Comparing these values with the options Part viii gives the best answer.
(viii) 116 ± 2.78 x 14.4√5
2.776 when rounded gives 2.78 and 14.40486 when rounded gives 14.4
The rest are incorrect.