Question

Consider the reaction n2 + 3 h2 → 2 nh3. How much nh3 can be produced from the reaction of 74. 2 g of n2 and 14. 0 moles of h2?

Answer 1

Convert 74.2 g N₂ to moles. (N₂ molar mass ≈ 28.014 g/mol)

(74.2 g) (1/28.014 mol/g) ≈ 2.65 mol N₂

According to the balanced reaction, 1 mol N₂ and 3 mol H₂ get consumed together to produce 2 mol NH₃, which means we consume up to

3 (2.65 mol N₂) ≈ 7.95 mol H₂

That is, all the N₂ is consumed and we have an excess of about 6.05 mol H₂. We end up with

2 (2.65 mol N₂) ≈ 5.30 mol NH₃

or (with NH₃ molar mass ≈ 17.031 g/mol)

(5.30 mol) (17.031 g/mol) ≈ 90.3 g NH₃