Answer:
3.213J/mol
Step-by-step explanation:
first specific heat capacity of water = 4200J/Kg K
Q=mass×temperature difference×specific heat capacity
Q=1.53×(24.3-20)×4200
Q=25.704 J
heat of solution= quantity of heat ÷ amount of substance
heat of solution= 25.704÷8
heat of solution= 3.213J/mol