Consider an urn with 7 black balls, 3 yellow balls, and 4 orange balls. If 3 balls are chosen randomly with replacement, what is the probability that the first is yellow, the second is orange, and the

Sauer asked Oct 3, 2023

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Sauer asked Oct 3, 2023

by Sauer

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12 votes

Answer:

1.79% chance or
(6)/(343)

Explanation:

7+3+4=14

chance of yellow
(3)/(14)

chance of orange
(4)/(14)

(3)/(14) * (4)/(14) *(4)/(14) = (6)/(343)

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