Question

What are the coordinates of the hole in the graph of the function?

f (x) = x^2 − 3x − 10
x−5

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Answer 1

The hole is at (5,7)

Explanation:

x^2 − 3x − 10

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x−5

Factor the numerator

(x-5)(x+2)

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x−5

There is a hole at x=5 since it will cancel in the numerator and the denominator

f(x) = x+2 and letting x = 5

f(5) = 5+2

The hole is at (5,7)