Answer:
48.37 degrees
Explanation:
c = AB = sqrt((9-7)² + (2-7)²) = sqrt(4+25) = sqrt(29)
b = AC = sqrt((5-7)² + (3-7)²) = sqrt(4+16) = sqrt(20)
a = BC = sqrt((5-9)² + (3-2)²) = sqrt(16+1) = sqrt(17)
A = angle at A
B = angle at B
C = angle at C
cos(A) = (b²+c²-a²)/(2bc) = (20+29-17)/2sqrt(20)sqrt(29) =
= 32/48.16637832... = 0.664363839...
A = acos(0.664363839...) = 48.366461... degrees