Question

A woman buys 50 eggs for $6.60. Some cost 12 cents each and the rest 14 cents each.

How many of each kind of eggs has she bought?​

Answer 1

She bought 20 eggs that were 12 cents, and she bought 30 eggs that were 14 cents.

Explanation:

Create a system of equations where x is the number of 12 cent eggs and y is the number of 14 cent eggs.

x + y = 50

0.12x + 0.14y = 6.6

Solve by elimination by multiplying the top equation by -0.12:

-0.12x - 0.12y = -6

0.12x + 0.14y = 6.6

Add these together and solve for y:

0.02y = 0.6

y = 30

So, she bought 30 eggs that were 14 cents. Plug in 30 as y into one of the equations, and solve for x:

x + y = 50

x + 30 = 50

x = 20

So, she bought 20 eggs that were 12 cents.

She bought 20 eggs that were 12 cents, and she bought 30 eggs that were 14 cents.