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What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force is applied

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Answer:

The friction coefficient's minimum value will be "0.173".

Step-by-step explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒
F_(net)=ma


=5* 1.7


=8.5 \ N

(b)

For m₃,

⇒
ma=\mu m_3 g

Or,

⇒
\mu=(a)/(g)


=(1.7)/(9.8)


=0.173

What is the minimum value of the friction coefficient between the boxes that will-example-1
User Walden Leverich
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