Question

Please help me (: ALgebra 2!!!!!!!!!!!!!!!!!!!!!

Answer 1

`(3x+1)/(x), x\\eq -1`

Explanation:

We can start by combining the fractions in the numerator. We can multiply them by x/x and x + 1/x + 1 respectively to get a common denominator of x(x + 1).

`(4)/(x+1)*(x)/(x) +(2)/(x) *(x+1)/(x+1)\\\\(4x)/(x(x+1))+(2x+2)/(x(x+1))\\\\(6x+2)/(x(x+1))`

Now we can rewrite an simplify:

`((6x+2)/(x(x+1)) )/((2)/(x+1) )\\\\\\(6x+2)/(x(x+1))*(x+1)/(2) \\\\(3x+1)/(x)`

The domain would be x ≠ -1 because the starting domain is
`x\\eq -1; x\\eq 0` and it changed to
`x\\eq 0`, so for the two fractions to be equal, the domain would be
`x\\eq -1`.