Question

An electron with a charge of -1.6 x 10-19 C experiences a force of 9.2 x 10-15 N. What is the intensity of the electric field?

Answer 1

Step-by-step explanation:

`E=(q)/(F)` where q is the charge of the electron and F is the electrostatic force. Filling in:

`E=(-1.6*10^(-19))/(9.2*10^(-15))` which gives you an electric field magnitude of

E = -1.7 ×
`10^{-5` C/N