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Find the magnitude and angle of a vector given the components: Bx = 7, By=-5​

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Answer:


|B| = \sqrt{ {B _(x) }^(2) + {B _(y) }^(2) } \\ = \sqrt{ {7}^(2) + {5}^(2) } \\ = √(74) \\ = 8.6


let \: the \: angle \: be \: \theta \\ \tan(\theta) = (B _(y) )/(B _(x) ) \\ \tan( \theta) = ( - 5)/(7) \\ \theta = { \tan }^( - 1) ( ( - 5)/(7) ) \\ = 35.5 \degree

User Samiksha
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