Question

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Answer 1

The horizontal component of the vector ≈ -16.06

The vertical component of the vector ≈ 19.15

Step-by-step explanation:

The magnitude of the vector,
`\left | R \right |` = 25 units

The direction of the vector, θ = 130°

Therefore, we have;

The horizontal component of the vector, Rₓ =
`\left | R \right |` × cos(θ)

∴ Rₓ = 25 × cos(130°) ≈ -16.06

The horizontal component of the vector, Rₓ ≈ -16.06

The vertical component of the vector, R
`_y` =
`\left | R \right |` × sin(θ)

∴ R
`_y` = 25 × sin(130°) ≈ 19.15

The vertical component of the vector, R
`_y` ≈ 19.15

(The vector, R = Rₓ + R
`_y`

`\underset{R}{\rightarrow}` = Rₓ·i + R
`_y`·j

∴
`\underset{R}{\rightarrow}` ≈ -16.07·i + 19.15j)