Answer:
Explanation:
area including track=area of 2 semi circles+area of rectangle
=2×1/2×π×46²+86×65
=2116 π+5590
area of grass=2×1/2×π×40²+80×65=1600π+5200
≈10226.55 m²
area of track=2116π+5590-1600π-5200
=516π+390
≈2011.06 m²
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