Question

Determine the solution to the given equation.

4 + 3y = 6y – 5
A.
y = 3
B.
y = –3
C.
y = 1
D.
y = –1

Answer 1

A

Explanation:

y=3

Answer 2

`\huge\boxed{\sf y = 3}`

Explanation:

Given Equation:

4 + 3y = 6y - 5

Add 5 to both sides

4 + 5 + 3y = 6y

9 + 3y = 6y

Subtract 3y to both sides

9 = 6y - 3y

9 = 3y

Divide 3 to both sides

3 = y

OR

y = 3

`\rule[225]{225}{2}`