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What is the solution for the equation?
asked
Mar 4, 2022
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What is the solution for the equation?
Mathematics
high-school
Anatoly Vdovichev
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Anatoly Vdovichev
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Cross multiply
5(b3-2) = 2(3b2 - 2b2 -5)
5b3 - 10 = 6b3 - 4b2 - 10
5b3 = 6b3 - 4b2
0 = b3 - 4b2
0 = b2(b - 4)
b2 = 0 —> b = 0
b-4=0 —> b = 4
Pvrforpranavvr
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Mar 11, 2022
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Pvrforpranavvr
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