Question

What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g

Answer 1

`V'=1040ml`

Step-by-step explanation:

From the question we are told that:

Initial Volume
`V_1=10.5mL`

Initial Aciditity of
`HN0_3 pH_1=2.0g`

Finial Aciditity of
`HN0_3 pH_2=4.0g`

Generally the equation for Acidity &Volume Relationship is mathematically given by

`N_1V_1=N_2V_2`

Therefore

`V_2=(N_1V_2)/(N_2)`

`V_2=(10^(-2)*10.5)/(10^(-4))V_2=1050ml`

Therefore

Change in Water volume is

`V'=V_2-V_1`

`V'=1050ml-10ml`

`V'=1040ml`