191k views
2 votes
What are the roots of the equation x^2+8x+32=0 in simplest a+bi form?

1 Answer

3 votes

Answer:

x = -4 ± i4

Explanation:

This is a quadratic equation with coefficients {1, 8, 32}. We apply the quadratic formula to solve for x. The first step is to find the 'discriminant,' b^2 - 4 ac, which here is (8)^2 - 4(1)(32), or 64 - 128, or -64.

A negative discriminant indicates that this quadratic has two unequal complex roots.

-b ± √(b^2 - 4ac)

The formula is x = ----------------------------

2a

which, when evaluated at a = 1, b = 8 and c= 32, yields

-8 ± √(-64)

The formula is x = ----------------------------

2(1)

or:

-8 ± i√64

The formula is x = ----------------- = x = -4 ± i4

2

User PeterLiguda
by
8.9k points