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What fraction of a wavelength of a standing wave pattern is between resonances in a closed end tube?

User DavidG
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1 Answer

6 votes

Answer:


25\% of the wavelength is between resonances in a closed end tube.

Step-by-step explanation:

In an one end closed tube, the fundamental resonance occurs when a node is created at the closed end and an antinode is created in the open end.

Thus, for fundamental resonance, the entire length of the tube encloses one-fourth of the wavelength of the standing wave.

The formula to calculate the percentage of the wavelength in a closed end tube is given by


f=(L)/(\lambda)*100\%........................(1)

Here,
f is the required percentage,
L is the length of the tube and
\lambda is the wavelength of the standing wave.

Substitute
(\lambda)/(4) for
L into equation (1) o calculate the required percentage.


f=((\lambda)/(4))/(\lambda)*100\%\\~~~=25\%

User Nikhil K R
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