Question

A chemical reaction done at STP conditions is supposed to produce 0.011 moles of CO2 gas. How many liters of gas will that be?

Answer 1

V = 0.24 L.

Step-by-step explanation:

Hello there!

In this case, it is possible to approach this problem by using the ideal gas equation defined by:

`PV=nRT`

Whereas our unknown is V, volume, and we solve for it as follows:

`V=(nRT)/(P)`

Then since the STP conditions are ate 273.15 K and 1 atm, the volume of 0.011 moles of CO2 gas turns out to be:

`V=(0.011mol*0.08206(atm*L)/(mol*K)*273.15K)/(1atm)\\\\V=0.24L`

Regards!