Answer:
Explanation:
What is the margin of error if the sample size is 100, sample mean is 68.0, and standard deviation is 4.0
The Margin of error formula =
± z score × s/√n
Where s = standard deviation= 4
n= Number for samples = 100
z = z score of confidence interval
Margin of error = ± z × 4/√100
Margin of error = ±z × 4/10
=± z × 2/5
= ± z × 0.4
= ± 0.4z
Margin of error = ± 0.4z