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Hemendr · Answer 1 · 2022-07-06T10:32:13+0000

Answer:
$146\ in.$

Explanation:

Given

The dimension of the rectangular sandcastle is

length
$l=41\ in.$

width
$w=32\ in.$

Perimeter is the sum of the sides of rectangle

$\therefore\ \text{Perimeter= }2\left(l+w\right)\\\Rightarrow \text{Perimeter= }2(41+32)\\\Rightarrow \text{Perimeter= }2* 73\\\Rightarrow \text{Perimeter= }146\ in.$

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