Question

A 9.2 resistor and a 5.2 resistor are connected in series with a battery. The potential difference across the 5.2 resistor is measured as 12 V. Find the potential difference across the battery.

Answer 1

V = 33.12 V

Step-by-step explanation:

Given that,

A 9.2 resistor and a 5.2 resistor are connected in series with a battery.

The potential difference across the 5.2 resistors is measured as 12 V.

In series combination of resistors, the current is same throughout the circuit. Let I is the current. Using Ohm's law,

`I=(V)/(R)`

Put all the values,

`I=(12)/(5.2)\\\\I=2.30\ A`

The equivalent resistance is :

R = 9.2 + 5.2

= 14.4 ohms

Let V os the potential difference across the battery. So,

`V=2.3* 14.4\\\\V=33.12\ V`

So, the potential difference across the battery is equal to 33.12 V.